21 lines
574 B
Lua
21 lines
574 B
Lua
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local function add_space_to_english_word(input)
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-- 匹配纯英文单词并在单词后添加空格
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input = input:gsub("(%a+)", "%1 ")
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return input
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end
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-- 在候选项上屏时触发的函数
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function en_spacer(input, env)
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for cand in input:iter() do
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if cand.text:match("^[%a']+[%a']*$") then
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-- 如果候选项是纯英文单词，则在输入后添加一个空格
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cand = cand:to_shadow_candidate(cand.type, add_space_to_english_word(cand.text), cand.comment)
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end
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yield(cand)
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end
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end
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return en_spacer
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